Mid Function
Returns a Variant (String) containing a specified number
of characters from a string.
Syntax
Mid(string, start[, length])
The Mid function syntax has these named arguments:
| Part |
Description |
| string |
Required. String expression from which characters
are returned. If string contains Null, Null
is returned. |
| start |
Required; Long. Character position in string
at which the part to be taken begins. If start is
greater than the number of characters in string, Mid
returns a zero-length string (""). |
| length |
Optional; Variant (Long). Number of
characters to return. If omitted or if there are fewer than length
characters in the text (including the character at start),
all characters from the start position to the end of
the string are returned. |
Remarks
To determine the number of characters in string, use the Len
function.
Note Use the MidB
function with byte data contained in a string, as in double-byte character
set languages. Instead of specifying the number of characters, the
arguments specify numbers of bytes. For sample code that uses MidB,
see the second example in the example topic.
Mid Function Example
The first example uses the Mid function to return a specified
number of characters from a string.
Dim MyString, FirstWord, LastWord, MidWords
MyString = "Mid Function Demo" ' Create text string.
FirstWord = Mid(MyString, 1, 3) ' Returns "Mid".
LastWord = Mid(MyString, 14, 4) ' Returns "Demo".
MidWords = Mid(MyString, 5) ' Returns "Function Demo".
The second example use MidB and a user-defined function (MidMbcs)
to also return characters from string. The difference here is that the
input string is ANSI and the length is in bytes.
Function MidMbcs(ByVal str as String, start, length)
MidMbcs = StrConv(MidB(StrConv(str, vbFromUnicode), start, length), vbUnicode)
End Function
Dim MyString
MyString = "AbCdEfG"
' Where "A", "C", "E", and "G" are DBCS and "b", "d",
' and "f" are SBCS.
MyNewString = Mid(MyString, 3, 4)
' Returns ""CdEf"
MyNewString = MidB(MyString, 3, 4)
' Returns ""bC"
MyNewString = MidMbcs(MyString, 3, 4)
' Returns "bCd"
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